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1/4 xy = -15 <=> xy = -60
Dibentuk persamaan kuadrat dengn an akar-akarnya x dan y. Maka,
(z - x)(z - y) = 0
<=> z^2 - (x + y)z + xy = 0
<=> z^2 - 4z - 60 = 0
<=> (z + 6)(z - 10) = 0
<=> z = -6 atau z = 10
Jadi, x = -6 dan y = 10, atau x = 10 dan y = -6.