Tiga buah hambatan yaitu 8 Ω, 4 Ω dan 2Ω disusun secara paralel, maka besarnya hambatan total rangkaian tersebut adalah…
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R1 = 8 ΩR2 = 4 Ω
R3 = 2 Ω
Rp?
penyelesaian:
1/Rp = 1/R1 + 1/R2 + 1/R3
1/Rp = 1/8 + 1/4 + 1/2
1/Rp = 1/8 + 2/8 + 4/8
1/Rp = 7/8
Rp = 8/7 Ω
atau Rp = 1,14 Ω