Question

tiga buah hambatan R1=2Ω,R2=9Ω,R3=12Ω
disusun secara paralel. tentukan hambatan penggantinya​

Answer 1

Jawaban:

Rp = 25/36

Penjelasan:

1/Rp = 1/R1 + 1/R2 + 1/R3

1/Rp = 1/2 + 1/9 + 1/12

1/Rp = 18/36 + 4/36 + 3/36

1/Rp = 25/36

Rp = 25/36

Answer 2

Verified answer

Penjelasan:

[tex] \frac{1}{ \text{Rp}} = \frac{1}{ \text{R}_{1} } + \frac{1}{\text{R}_{2} } + \frac{1}{\text{R}_{3}} [/tex]

[tex] \frac{1}{\text{Rp}} = \frac{1}{2} + \frac{1}{9} + \frac{1}{12} [/tex]

[tex] \frac{1}{\text{Rp}} = \frac{18}{36} + \frac{4}{36} + \frac{3}{36} [/tex]

[tex] \frac{1}{\text{Rp}} = \frac{25}{36} [/tex]

[tex]\text{Rp} = \frac{36}{25} [/tex]

[tex]\text{Rp} = \bold{1,44 \: ohm}[/tex]