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3a+3b=18
a+b=6
a(a+b)(a+2b)=162
a(a+b)(a+b+b)=162
a(6)(6+b)=162
a(6+b)=27
6a+ab=27
6a+ab=27 dan a+b=6, dengan eliminasi diperoleh
6b-ab=9
b(6-a)=9
b(a+b-a)=9
b(b)=9
b=3
a+b=6
a+3=6
a=3
suku pertama: a=3
suku kedua: a+b=6
suku ketiga: a+2b=9