_____________________________
= ∫(-16 - 6x⁴) / x² dx
= ∫(-16x-²) - 6x² dx
= -1/1 . -16/x - 6x³/3 + c
= 16/x - 2x³ + c
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❐ Integral
_____________________________
= ∫(-16 - 6x⁴) / x² dx
= ∫(-16x-²) - 6x² dx
= -1/1 . -16/x - 6x³/3 + c
= 16/x - 2x³ + c