Odpowiedź:
[tex]\displaystyle y=log_{\frac{1}{2} }x\\D=(0,+\infty)\\Z_w=R\\y=log_{\frac{1}{2} }(x+3)\\D=(-3,+\infty)\\Z_w=R[/tex]
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Odpowiedź:
[tex]\displaystyle y=log_{\frac{1}{2} }x\\D=(0,+\infty)\\Z_w=R\\y=log_{\frac{1}{2} }(x+3)\\D=(-3,+\infty)\\Z_w=R[/tex]