Sederhanakanlah!
1.
[tex]3 \sqrt{2} \times 2 \sqrt{10} - \sqrt{20} = [/tex]
2.
[tex] \frac{10 \sqrt{6} }{5 \sqrt{3} } + 3 \sqrt{72} - \sqrt{32} = [/tex]
3.
[tex] \sqrt{300} - 3 \sqrt{15} \times \sqrt{6} = [/tex]
(Tolong pakai cara)
1.
[tex]3 \sqrt{2} \times 2 \sqrt{10} - \sqrt{20} = [/tex]
2.
[tex] \frac{10 \sqrt{6} }{5 \sqrt{3} } + 3 \sqrt{72} - \sqrt{32} = [/tex]
3.
[tex] \sqrt{300} - 3 \sqrt{15} \times \sqrt{6} = [/tex]
(Tolong pakai cara)
Jawaban:
3√2 × 2√10 - √20
6√20 - √20 = 5√20
....
10√6/5√3 + 3√72 - √32
2√2 + 3.√36.√2 - √16.√2
2√2 + 18√2 - 4√2
16√2
.....
√300 - 3√15 × √6
√300 - 3√90
10√3 - 3.√9.√10
10√3 - 9√10