Tentukanlah bentuk sederhana dari eksponensial berikut[tex] \frac{(3 \sqrt{2} + 2 \sqrt{3 }) {}^{2} .... Question from @andromedaldebaran12

Jawaban:

$\frac{(3 \sqrt{2} + 2 \sqrt{3 }) {}^{2} } { \sqrt{2 } - \sqrt{3} } \\$

$= \frac{(3 \sqrt{2} + 2 \sqrt{3 }) {}^{2} } { \sqrt{2 } - \sqrt{3} } \times \frac{ \sqrt{2} + \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \\$

$= \frac{(3 \sqrt{2}) {}^{2} + (2 \sqrt{3} ) {}^{2} }{ \sqrt{2} - \sqrt{3} } \times \frac{ \sqrt{2} + \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \\$

$= \frac{18 + 12 }{ \sqrt{2} - \sqrt{3} } \times \frac{ \sqrt{2} + \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \\$

$= \frac{30}{ \sqrt{2} - \sqrt{3} } \times \frac{ \sqrt{2} + \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \\$

$= \frac{30 \sqrt{2} + 30 \sqrt{3} }{2 - 3} \\$

$= \frac{30 \sqrt{2} + 30\sqrt{3} }{ - 1} \\$

$= - 30( \sqrt{2} + \sqrt{3} ) \\$

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♬ Mapel: Matematika

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♬ Materi: Bab 1.1 - Bentuk akar, eksponen, logaritma

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♬ Kode Kategorisasi: 10.2.1.1

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