Question

[tex]f \: (x) =a + b \\ f = ( - 2) = - 4 \\ f( - 6) = 12[/tex]
tentukan:
a) rumus fungsi?
b) f (-10) =
c) f (10) =

***pakai penjelasan***​

Answer 1

Penjelasan dengan langkah-langkah:

f(-2) = -4 → -2a + b = -4

f(-6) = 12 → -6a + b = 12 –

--------------------

4a = -16

a = -4

-2a + b = -4

-2(-4) + b = -4

8 + b = -4

b = -4 - 8

b = -12

——————————

a)

f(x) = ax + b

f(x) = -4x - 12

b)

f(-10) = -4(-10) - 12

f(-10) = 40 - 12

f(-10) = 28

c)

f(10) = -4·10 - 12

f(10) = -40 - 12

f(10) = -52

Answer 2

Penjelasan dengan langkah-langkah:

a.

f(x) = AX + b

f(x) = -4x + -12

b.

f(x) = -4x + -12

f(-10) = -4(-10) + -12

f(-10) = 4(10) + -12

f(-10) = 40 + -12

f(-10) = 40 - 12

f(-10) = 28

c

f(x) = -4x + -12

f(10) = -4(10) - 12

f(10) = -52