diketahui persamaan
[tex] \sqrt{ {3}^{2x + 1} } = {9}^{x - 2} [/tex]
tentukan nilai X
[tex] \sqrt{ {3}^{2x + 1} } = {9}^{x - 2} [/tex]
tentukan nilai X
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Penyelesaian:
√(3^(2x+1))=9^x-2
3^½(2x+1)=3^2(x-2)
x+½=2(x-2)
x+½=2x-4
4½=x
Penjelasan dengan langkah-langkah: