Materi : Limit Fungsi
Lim ( x => 2 ) = [ x = 2 ]
\________________/
= ( x² + 1 )/( x² - 3 )
= [ (2)² + 1 ]/[ (2)² - 3 ]
= [ 4 + 1 ]/[ 4 - 3 ]
= 5/1
= { 5 }
Semoga bisa membantu
= 2² + 1 / 2² - 3
= ( 2.2 ) + 1 / ( 2.2 ) - 3
= 4 + 1 / 4 - 3
= 5
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Materi : Limit Fungsi
Lim ( x => 2 ) = [ x = 2 ]
\________________/
= ( x² + 1 )/( x² - 3 )
= [ (2)² + 1 ]/[ (2)² - 3 ]
= [ 4 + 1 ]/[ 4 - 3 ]
= 5/1
= { 5 }
Semoga bisa membantu
= 2² + 1 / 2² - 3
= ( 2.2 ) + 1 / ( 2.2 ) - 3
= 4 + 1 / 4 - 3
= 5/1
= 5