Question

Q.ueesss
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[tex]\sf{{{f(x) = x!! + 2x² }}}[/tex]
[tex]\sf{{{f(10) = ...}}}[/tex]
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Answer 1

Penyelesaian :

f(X) = X!! + 2X^2

f(10) = 10!! + 2(10^2)

f(10) = (10 × 8 × 6 × 4 × 2) + 2(10 × 10)

f(10) = (80 × 6 × 4 × 2) + 2(100)

f(10) = (480 × 4 × 2) + (2 × 100)

f(10) = (1.920 × 2) + 200

f(10) = 3.840 + 200

f(10) = 4.040

Answer 2

Jawaban:

Penjelasan dengan langkah-langkah:

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⭐ SOAL ⭐

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f(×) = ×!! + 2×^2

f(10) =

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↪ JAWABAN ↩

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10!!

=10×8×6×4×2

=80×6×4×2

=480×4×2

= 1,920×2

=3,840

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f (×) = 10!! + 2×^2

f (10) = (10×8×6×4×2) + 2(10^2)

f (10) = ( 80×6×4×2) + 2 (100)

f (10) = (480×4×2) + 2 (100)

f (10) = ( 1,920×2) + 2 (100)

f (10) = ( 3,840 ) + 2 (100)

f (10) = 3,840 + 200

f (10) = 4,040

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