Question

[tex] 3\sqrt{36} + 2 \sqrt{ \sqrt{16} } [/tex]
[tex]1 - 2 + 3 - 4 + 5........... + 99[/tex]
RedAsta muncul dong (⁠｡⁠•̀⁠ᴗ⁠-⁠)⁠✧​

Answer 1

Verified answer

[tex]\displaystyle\tt~3\sqrt{36} + 2 \sqrt{ \sqrt{16} } = 3 \sqrt{ {6}^{2} } + 2 \sqrt[4]{16} \\ \displaystyle\tt~ = 3.6 + 2 \sqrt[4]{ {2}^{4} } \\ \displaystyle\tt~ = 18 + 2.2 \\ \displaystyle\tt~ = 18 + 4 \\ \displaystyle\tt~ = 22[/tex]

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[tex]\boxed{\displaystyle\tt~ 1 - 2 + 3 - 4 + 5 ... + n = -1 × n}[/tex]

[tex]\displaystyle\tt~1 - 2 + 3 - 4 + 5..... + 99 \\ \displaystyle\tt~ = (49)(-1) \\ \displaystyle\tt~ = -49 + 99 \\ \displaystyle\tt~ = 50[/tex]