a
[tex] \sqrt{16 \div 4} [/tex]
b
[tex](5.2) {?}^{2} [/tex]
porfa me lo resulven paso a paso hoyyy
[tex] \sqrt{16 \div 4} [/tex]
b
[tex](5.2) {?}^{2} [/tex]
porfa me lo resulven paso a paso hoyyy
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Respuesta:
A √16:4=4 B (5×6)=10 el dos ba aribita del 10