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[tex]\begin{aligned} 2x-4y&=8 \\ 2x &= 8 + 4y \\ x &= \frac{8 + 4y}{2} \\&= \frac{8}{2} + \frac{4y}{2} \\&= \boxed{\bold{\underline{4 + 2y}}} \end{aligned}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 06 - 07 - 2023}}[/tex]
2x - 4y = 8
2(x - 2y) = 8
2(x - 2y)/2 = 8/2
x - 2y = 4
x = 4 + 2y.
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[tex]\begin{aligned} 2x-4y&=8 \\ 2x &= 8 + 4y \\ x &= \frac{8 + 4y}{2} \\&= \frac{8}{2} + \frac{4y}{2} \\&= \boxed{\bold{\underline{4 + 2y}}} \end{aligned}[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at | 06 - 07 - 2023}}[/tex]
2x - 4y = 8
2(x - 2y) = 8
2(x - 2y)/2 = 8/2
x - 2y = 4
x = 4 + 2y.