Question

Soal :
1. 2²²⁰ ÷ 2²¹⁰ = ..
[tex] \\ [/tex]
2. (1 + 1 + 1 + 1 + 1 + 1 + 1)! = ..
[tex] \\ [/tex]
3. ⁴log 64 × ³log 27 = ..
[tex] \\ [/tex]
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Answer 1

1. 2^220 ÷ 2^210= 2^( 220 - 210 )= 2^102. ( 1 + 1 + 1 + 1 + 1 + 1 + 1 )!= ( 2 + 2 + 2 + 1 )!= ( 4 + 3 )!= 7!= 7 × 6 × 5 × 4 × 3 × 2 × 1= 42 × 20 × 6= 840 × 6= 5.0403. ⁴log 64 × ³log 27= ⁴log 4³ × 3 log 3³= 3 × ⁴log 4 × 3= 3 × 3= 9~Koreksi~⃢~ Opung~⃠⃫⃟⃤᳗᳐