eksponen
2^(³√p) = 4^(⁴√p)
2^(³√p) = 2^(2 ⁴√p)
³√p = 2 ⁴√p
kedua ruas dipangkatkan 12
p⁴ = 2¹² p³
p³(p - 2¹²) = 0
p = 0 atau p = 2¹² = 4096
p = {0 , 4096}
Jawaban:
p = {0, 4096}
Penjelasan dengan langkah-langkah:
[tex]2 {}^{ \sqrt[3]{p} } = {2}^{2 \sqrt[4]{p} } [/tex]
[tex] \sqrt[3]{p} = 2 \sqrt[4]{p} [/tex]
[tex] \sqrt[3]{p} {}^{12} = (2 \sqrt[4]{p} ) {}^{12} [/tex]
[tex] {p}^{4} = 4096p {}^{3} [/tex]
[tex]p {}^{4} - 4096p {}^{3} = 0[/tex]
[tex] {p}^{3} \times (p - 4096) = 0[/tex]
[tex] {p}^{3 } = 0 \\ p - 4096 = 0[/tex]
[tex]p = 0 \\ p = 4096[/tex]
[tex]p1 = 0 \:, p2 = 4096[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alfat}}[/tex]
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eksponen
2^(³√p) = 4^(⁴√p)
2^(³√p) = 2^(2 ⁴√p)
³√p = 2 ⁴√p
kedua ruas dipangkatkan 12
p⁴ = 2¹² p³
p³(p - 2¹²) = 0
p = 0 atau p = 2¹² = 4096
p = {0 , 4096}
Verified answer
Jawaban:
p = {0, 4096}
Penjelasan dengan langkah-langkah:
[tex]2 {}^{ \sqrt[3]{p} } = {2}^{2 \sqrt[4]{p} } [/tex]
[tex] \sqrt[3]{p} = 2 \sqrt[4]{p} [/tex]
[tex] \sqrt[3]{p} {}^{12} = (2 \sqrt[4]{p} ) {}^{12} [/tex]
[tex] {p}^{4} = 4096p {}^{3} [/tex]
[tex]p {}^{4} - 4096p {}^{3} = 0[/tex]
[tex] {p}^{3} \times (p - 4096) = 0[/tex]
[tex] {p}^{3 } = 0 \\ p - 4096 = 0[/tex]
[tex]p = 0 \\ p = 4096[/tex]
[tex]p1 = 0 \:, p2 = 4096[/tex]
[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alfat}}[/tex]