[tex] \\ [/tex]
dik data :
5 6 7 3 3 4 5 3 2
tentukan :
-modus
-mean
-range(jangkauan)
-median
pakai cara
[tex] \\ [/tex]
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dik data :
5 6 7 3 3 4 5 3 2
tentukan :
-modus
-mean
-range(jangkauan)
-median
JAWAB :
URUTKAN DATA :
2 3 3 3 4 5 5 6 7
MAKA :
MODUS => NILAI YANG SERING MUNCUL :
= 3
MEAN => B.DATA / T.DATA :
= (2 + 3 + 3 + 3 + 4 + 5 + 5 + 6 + 7)/9
= (5 + 6 + 9 + 11 + 7)/9
= (11 + 20 + 7)/9
= (31 + 7)/9
= 38/9
= 4,2
RANGE => T9 - T1
= 7 - 2
= 5
MEDIAN => NILAI TENGAH :
= 4
[tex]{\color{aqua}{\boxed{\tt{CaptainInnovaGR}}\:}}[/tex]
Verified answer
5 6 7 3 3 4 5 3 2
Modus :
5 = 2
6 = 1
7 = 1
3 = 3
4 = 1
2 = 1
makaa, modus nya adalh 3 krna memiliki frekuensi yg pling tinggi (3 kali muncul)
Mean :
m = ( 2 + 3 + 3 + 3 + 4 + 5 + 5 + 6 + 7)/9
m = 39/9
m = 4,2
Range :
r = Xmax - Xmin
r = 7 - 2
r = 5
Median (nilai tengah) :
urutkan data dari yg terkecil =
2 3 3 3 4 5 5 6 7
= 4 (median)