Question

q.

[tex]lim \frac{x - 16}{ \sqrt{x } -4 } \\ {}^{x -> 5 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]
note:
yg gampang2 aja dulu​

Answer 1

Verified answer

Jawaban:

[tex] \sqrt{5} + 4[/tex]

Penjelasan dengan langkah-langkah:

[tex]\displaystyle\lim_{x \to 5} \frac{x - 16}{ \sqrt{x} - 4} [/tex]

[tex]\displaystyle~~ \: ~= \frac{5 - 16}{ \sqrt{5} - 4} [/tex]

[tex]\displaystyle~~ \: ~= \frac{ - 11}{ \sqrt{5} - 4} [/tex]

[tex]\displaystyle~~ \: ~= \frac{ - 11}{ \sqrt{5} - 4 } \times \frac{ \sqrt{5} + 4 }{ \sqrt{5} + 4 } [/tex]

[tex]\displaystyle~~ \: ~= \frac{ - 11( \sqrt{5} + 4) }{ 5 - 16} [/tex]

[tex]\displaystyle~~ \: ~= \frac{ - 11( \sqrt{5} + 4)}{ - 11} [/tex]

[tex]\displaystyle~~ \: ~ = \sqrt{5} + 4[/tex]

[tex] \\ [/tex]

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Answer 2

Jawaban:

4 + √5

Penjelasan dengan langkah-langkah:

Tinggal subtitusi

[tex] \displaystyle \lim_{x \to5} \: \frac{x - 16}{ \sqrt{x } -4 }[/tex]

[tex] = \frac{5 - 16}{ \sqrt{5} - 4 }[/tex]

[tex] = \frac{ - 11}{ \sqrt{5} - 4 } [/tex]

[tex] = \frac{ - 11( 4+\sqrt{5}) }{-11 } [/tex]

[tex] = \bold{4 + \sqrt{5} }[/tex]