Materi : Bentuk Akar dan Pangkat
√16
= √( 4 . 4 )
= √(4²)
= 4²/²
= 4¹
= 4
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
akar dari 16
= √(4 × 4)
= ²√4²
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Materi : Bentuk Akar dan Pangkat
√16
= √( 4 . 4 )
= √(4²)
= 4²/²
= 4¹
= 4
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
akar dari 16
√16
= √(4 × 4)
= ²√4²
= 4