Question

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[tex] \frac{ {8}^{5x + 2} }{ {64}^{x - 2} } = {8}^{2x - 3} [/tex]
nilai x = ...

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Answer 1

[tex]\begin{aligned} \sf \frac{8^{5x + 2}}{64^{x - 2}} &= \sf 8^{2x - 3} \\ \sf \frac{8^{5x + 2}}{(8^2)^{x - 2}} &= \sf 8^{2x - 3} \\ \sf \frac{8^{5x + 2}}{8^{2x - 4}} &= \sf 8^{2x - 3} \\ \sf 8^{5x - 2x + 2 + 4} &= \sf 8^{2x - 3} \\ \sf \not\!8^{3x + 6} &= \sf \not\!8^{2x - 3} \\ \sf 3x + 6 &= \sf 2x - 3 \\ \sf 3x - 2x&= \sf -3 - 6 \\ \sf x&= \sf -9\end{aligned}[/tex]

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