JIka :
A = 21² + ⁴log 64
B = 5!! × 3!!
C = √144 - 5²
Maka Tentukan :
A + B + C = ..
[tex] \\ \\ [/tex]
..
janlup cara-!
A = 21² + ⁴log 64
B = 5!! × 3!!
C = √144 - 5²
Maka Tentukan :
A + B + C = ..
[tex] \\ \\ [/tex]
..
janlup cara-!
Jawaban:
476
Penjelasan dengan langkah-langkah:
A = 21² + ⁴log 64
= (21×21) + ⁴log4³
= 441 + 3
= 444
B = 5!! × 3!!
= (5×3) × 3
= 15 × 3
= 45
C = √144 - 5²
= √12² - (5×5)
= 12 - 25
= -13
Nilai A + B + C
= 444 + 45 + (-13)
= 489+ (-13)
= 476