Question

[tex]\huge\bf \frac{ { ({2}^{3}) }^{ - 2} \times { {4}^{3} }^{2} }{ {16}^{3} } = ....?[/tex]

ho'oh hmmm...​

Answer 1

[tex]\tt \frac{(2^3)^{-2}\times 4^{3^2}}{16^3}\\ \\= \frac{2^{-6}\times (2^2)^{9}}{(2^4)^{3}}\\ \\= \frac{2^{-6}\times 2^{18}}{2^{12}}\\ \\= 2^{-6+18-12}\\\\= 2^{0}\\\\=1[/tex]