Kaidah eksponennᵃ×nᵇ = nᵃ⁺ᵇnᵃ÷nᵇ = nᵃ⁻ᵇ
(5³×5⁻²)÷5² = (5³⁺⁽⁻²⁾)÷5² =(5³⁻²)÷5² =5¹ ÷ 5² =5¹⁻² =5⁻¹
∵ n⁻ᵃ = 1/(nᵃ) ∴5⁻¹ = 1/(5¹) = ¹/₅
hasilnya adalah ¹/₅
5^3 × 5^-2/5²
=125×1/5²×1/5²
=125×1/5⁴
=125/625
=1/5
Semoga bermanfaat
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Verified answer
Kaidah eksponen
nᵃ×nᵇ = nᵃ⁺ᵇ
nᵃ÷nᵇ = nᵃ⁻ᵇ
(5³×5⁻²)÷5² = (5³⁺⁽⁻²⁾)÷5² =
(5³⁻²)÷5² =
5¹ ÷ 5² =
5¹⁻² =
5⁻¹
∵ n⁻ᵃ = 1/(nᵃ) ∴
5⁻¹ = 1/(5¹) = ¹/₅
hasilnya adalah ¹/₅
Penyelesaian
5^3 × 5^-2/5²
=125×1/5²×1/5²
=125×1/5⁴
=125/625
=1/5
Semoga bermanfaat