Question

[tex] ({x + 4}^{2}) + {y}^{2} = 9[/tex]
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Answer 1

[tex] \bf(x + {4}^{2} ) + {y}^{2} = 9 \\ (x + 16) + {y}^{2} = 9 \\ x + 16 + {y}^{2} = 9 \\ x = 9 - 16 - {y}^{2} \\ x = - 7 - {y}^{2} \\ [/tex]