Jawab:
[tex]1. \ \frac{6x^2 + x - 2}{4x^2 -1}[/tex]
[tex]= \frac{6x^2 + 4x - 3x - 2}{(2x)^2 -1^2} \\ \\= \frac{2x (3x + 2) - 1(3x + 2)}{(2x)^2 -1^2} \\ \\= \frac{(2x - 1)(3x + 2)}{(2x - 1)(2x + 1)} \ (atas \ dan \ bawah \ yang \ sama \ dihilangkan)\\ \\= \frac{3x + 2}{2x+1}[/tex]
[tex]2. \ \frac{3x}{2} \div \frac{6x^2}{4} = \frac{3x}{2} \times \frac{4}{6x^2}[/tex]
[tex]= \frac{12x}{12x^2} \\ \\= \frac{1}{x} \ atau \ x^{-1}[/tex]
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Verified answer
Jawab:
[tex]1. \ \frac{6x^2 + x - 2}{4x^2 -1}[/tex]
[tex]= \frac{6x^2 + 4x - 3x - 2}{(2x)^2 -1^2} \\ \\= \frac{2x (3x + 2) - 1(3x + 2)}{(2x)^2 -1^2} \\ \\= \frac{(2x - 1)(3x + 2)}{(2x - 1)(2x + 1)} \ (atas \ dan \ bawah \ yang \ sama \ dihilangkan)\\ \\= \frac{3x + 2}{2x+1}[/tex]
[tex]2. \ \frac{3x}{2} \div \frac{6x^2}{4} = \frac{3x}{2} \times \frac{4}{6x^2}[/tex]
[tex]= \frac{12x}{12x^2} \\ \\= \frac{1}{x} \ atau \ x^{-1}[/tex]