Qz(9/10)[tex] \: [/tex][tex] \lim\limits_{x \rightarrow2} \: \dfrac{ {2x}^{2} + 6x}{2x + 6} [/tex]Go.... Question from @ErichelFr

August 2022 2 24 Report

Qz(9/10)
[tex] \: [/tex]
[tex] \lim\limits_{x \rightarrow2} \: \dfrac{ {2x}^{2} + 6x}{2x + 6} [/tex]

Good Luck!

$\lim\limits_{x \rightarrow2} \: \dfrac{ {2x}^{2} + 6x}{2x + 6} \\ = \frac{2( {2}^{2}) + 6(2) }{2(2) + 12} \\ = \frac{2(4) + 12}{4 + 6} \\ = \frac{8 + 12}{10} \\ = \frac{20}{10} \\ = 2$

$\:$

»Detail Jawaban:

Mapel: Matematika
Kelas: XI
Materi: Limit fungsi

#AyoBelajar!

2 votes Thanks 6

JavierSKho13 koreksi ^^ baris ketiga 6(2) harusnya 12

ErichelFr pasti udah ngantuk :v

BNP999

Jawaban:

Pembahasan

Limit Pemfaktoran

$\lim\limits_{x \rightarrow2} \: \dfrac{ {2x}^{2} + 6x}{2x + 6}$

$\lim\limits_{x \rightarrow2} \: \dfrac{ 2x(x + 3)}{2(x + 3)}$

Eliminasi, coret (x + 3).

$\lim\limits_{x \rightarrow2} \: \dfrac{ 2x \: \cancel{(x + 3)}}{2 \: \cancel{(x + 3)} }$

Maka, akan menghasilkan sebagai berikut:

= $\frac{2x}{2} \\$

Karena nilai x → menuju 2, kita substitusikan.

= $\frac{2(2)}{2} \\$

= $\frac{4}{2} \\$

= 2

Kesimpulan

Jadi, nilai dari $\lim\limits_{x \rightarrow2} \: \dfrac{ {2x}^{2} + 6x}{2x + 6}$ tersebut adalah 2.

11 votes Thanks 15

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