Jawaban:
[tex]x \geqslant \frac{26}{3} [/tex]
= x ≤ 1
x ≤ 1= x = {1, 0, -1, 2, ...}
Penjelasan dengan langkah-langkah:
[tex] \frac{2}{3x - 1} \geqslant \frac{5}{x + 4} [/tex]
= 2.(x + 4) ≥ 5.(3x - 1)
= 2.x + 2.4 ≥ 5.3x - 5.1
= 2x + 8 ≥ 15x - 5
= 2x - 15x ≥ -8 - 5
= -13x ≥ -13
= x ≤ -13 ÷ -13
x ≤ 1
x = {1, 0, -1, 2, ...}
[tex]\sf\bf{ \frac{2}{3x - 1} \geqslant \frac{5}{x + 4} } \\ \\\rm 2(x + 4) \geqslant 5(3x - 1) \\ \\ \rm \: 2x + 8 \geqslant 15x - 5 \\ \\ \rm \: 2x - 15x \geqslant - 5 - 8 \\ \\ \rm \: - 13x \geqslant { - 13} \\ \\ \rm \: x \geqslant \frac{ - 13}{ - 13} \\ \\ \rm \: x \geqslant 1 [/tex]
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Jawaban:
[tex]x \geqslant \frac{26}{3} [/tex]
= x ≤ 1
x ≤ 1= x = {1, 0, -1, 2, ...}
Penjelasan dengan langkah-langkah:
[tex] \frac{2}{3x - 1} \geqslant \frac{5}{x + 4} [/tex]
= 2.(x + 4) ≥ 5.(3x - 1)
= 2.x + 2.4 ≥ 5.3x - 5.1
= 2x + 8 ≥ 15x - 5
= 2x - 15x ≥ -8 - 5
= -13x ≥ -13
= x ≤ -13 ÷ -13
= x ≤ 1
x ≤ 1
x = {1, 0, -1, 2, ...}
Verified answer
Penjelasan dengan langkah-langkah:
[tex]\sf\bf{ \frac{2}{3x - 1} \geqslant \frac{5}{x + 4} } \\ \\\rm 2(x + 4) \geqslant 5(3x - 1) \\ \\ \rm \: 2x + 8 \geqslant 15x - 5 \\ \\ \rm \: 2x - 15x \geqslant - 5 - 8 \\ \\ \rm \: - 13x \geqslant { - 13} \\ \\ \rm \: x \geqslant \frac{ - 13}{ - 13} \\ \\ \rm \: x \geqslant 1 [/tex]