Q. [tex] \huge{\boxed{\sf ↓soal ↓}}[/tex]..f(x) = 5x² × 20¹ + 10x²f(4) = ........ Question from @basih0239

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f(x) = 5x² × 20¹ + 10x²

f(4) = 5(4)² × 20¹ + 10(4)²

f(4) = 5(16) × 20 + 10(16)

f(4) = 80 × 20 + 160

f(4) = 1600 + 160

f(4) = 1760

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Ninmy!

3 votes Thanks 4

myiinx

Jawaban:

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Diketahui :

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Ditanya :

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Dijawab :

f(x) = 5x² × 20¹ + 10x²
f(4) = 5(4²) × 20¹ + 10(4²)
f(4) = 5(4 + 4 + 4 + 4) × 20¹ + 10(4²)
f(4) = 5(8 + 8) × 20¹ + 10(4²)
f(4) = 5(16) × 20¹ + 10(4²)
f(4) = ((32 + 32) + 16) × 20¹ + 10(4²)
f(4) = (64 + 16) × 20¹ + 10(4²)
f(4) = 80 × 20¹ + 10(4²)
f(4) = 80 × 20 + 10(4 + 4 + 4 + 4)
f(4) = 80 × 20 + 10(8 + 8)
f(4) = 80 × 20 + 10(16)
f(4) = 80 × 20 + ((48 + 48 + 48) + 16)
f(4) = 80 × 20 + ((96 + 48) + 16)
f(4) = 80 × 20 + (144 + 16)
f(4) = ( 80 × 20 ) + 160
f(4) = 1.600 + 160
$\tt\red{{{f(4) =}}}$ $\sf\underline \color{red}\boxed{1.760}$

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maka, nilai dari $\tt\red{{{f(4) }}}$ adalah $\sf\underline \color{red}\boxed{1.760}$

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- P ࿐ྂ

4 votes Thanks 13