Question

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[tex] \sf \lim_{ x \to8} \: \frac{2x + 2 + x}{x + 2} [/tex]
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[tex]\red{\boxed{\green{\boxed{\orange{\tt{\star~\pink{ Pake Cara,,thanks}~\star}}}}}}[/tex]​

Answer 1

[tex] \displaystyle\sf \lim_{ x \to8} \: \dfrac{2x + 2 + x}{x + 2}[/tex][tex] \sf = \dfrac{2(8) + 2 + 8}{8 + 2} [/tex][tex] \sf = \dfrac{16 + 2 + 8}{8 + 2} [/tex][tex] \sf = \dfrac{18 + 8}{10} [/tex][tex] \sf = \dfrac{26}{10} [/tex][tex] \sf = \dfrac{26 \div 2}{10 \div 2} [/tex][tex] \sf = \dfrac{13}{5} [/tex][tex] \sf = 2\dfrac{3}{5} [/tex]