Jawab:
Penjelasan dengan langkah-langkah:
limit 0/0
soal1
soal 2
lim x-> 3 (x³ - 27)/ (x³- 4x² + 3x)
lim x-> 3 (x - 3)(x²+ x +9)/ { x (x² - 4x + 3)}
lim x-> 3 (x - 3)(x²+ x +9)/ { x ( x - 1)(x - 3)}
lim x-> 3 (x²+ x +9)/ { x (x - 1)}
sun x = 3
lim = (9 + 9 + 9 )/ { 3( 2)}
lim = 27/6 = 4, 5
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Jawab:
Penjelasan dengan langkah-langkah:
limit 0/0
soal1
soal 2
lim x-> 3 (x³ - 27)/ (x³- 4x² + 3x)
lim x-> 3 (x - 3)(x²+ x +9)/ { x (x² - 4x + 3)}
lim x-> 3 (x - 3)(x²+ x +9)/ { x ( x - 1)(x - 3)}
lim x-> 3 (x²+ x +9)/ { x (x - 1)}
sun x = 3
lim = (9 + 9 + 9 )/ { 3( 2)}
lim = 27/6 = 4, 5