f(x) = 12x³ + x! - x² × √x + 5(x)
f(4) = ..
[tex] \\ \\ \\ [/tex]
f(4) = ..
[tex] \\ \\ \\ [/tex]
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Jawaban:
f(x) = 12x³ + x! - x² × √x + 5(x)
f(4) = ..
penyelesaian :
f(4) = 12(4)^3 + 4! - 4^2 × √4 + 5(4)
f(4) = 12(4×4×4) + (4×3×2) - (4×4) × 2 + (5×4)
f(4) = 12(16×4) + (12×2) - (16×2) + 20
f(4) = 12(64) + 24 - 32 + 20
f(4) = 768 + 24 - 32 + 20
f(4) = 792 - 32 + 20
f(4) = 760 + 20
f(4) = 780
f(x) = 12x³ + x! - x² × √x + 5(x)
f(4) = 12(4)³ + 4! - 4² × √4 + 5(4)
f(4) = 12(64) + (4 × 3 × 2 × 1) - (4 × 4) × √2² + 20
f(4) = 768 + (12 × 2) - 16 × 2 + 20
f(4) = 768 + 24 - 16 × 2 + 20
f(4) = 768 + 24 - 32 + 20
f(4) = 792 - 32 + 20
f(4) = 760 + 20
f(4) = 780