Nyatakan hasil penjumlahan dan pengurangan berikut ke dalam bentuk akarpaling sederhana[tex] \sqrt{2.... Question from @Zayang

September 2022 2 4 Report

Nyatakan hasil penjumlahan dan pengurangan berikut ke dalam bentuk akar
paling sederhana

[tex] \sqrt{200} - \sqrt{50} + \sqrt{32} [/tex]

Jawaban:

$\sqrt{100 \times 5} - \sqrt{25 \times 5} + \sqrt{16 \times 2}$

maka hasilnya adalah

$10 \sqrt{5} - 5 \sqrt{5} + 4 \sqrt{2}$

kalo bisa sih

$5 \sqrt{5} + 4 \sqrt{2}$

gomen bang kalo salah

1 votes Thanks 1

Zayang makasih

LeeSchool √200 = √100 × 2, bukan √100 × 5

aditiampratama181 maaf bang gomen ga liat

LeeSchool koreksi

LeeSchool ..

LeeSchool

- Penyelesaian soal-

$\:$

$\sf \: \sqrt{200} - \sqrt{50} + \sqrt{32}$

$\sf \: = \sqrt{100 \times 2} \: - \: \sqrt{25 \times 2} + \sqrt{16 \times 2}$

$\sf \: = \sqrt{10 {}^{2} \times 2 } - \sqrt{5 {}^{2} \times 2} + \sqrt{ {2}^{4} \times 2}$

$\sf \: = 10 \sqrt{2} - 5 \sqrt{2} + 4 \sqrt{2}$

$\sf \tt \: = (10 - 5 + 4) \sqrt{2}$

$\sf \tt \: = (5 + 4) \sqrt{2}$

$\tt \: = 9 \sqrt{2}$

$\sf \tt \: = 3 {}^{2} \sqrt{2}$

$\sf \tt \: = 3 \sqrt{2}$

2 votes Thanks 1

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