Tentukan nilai A, B,C, D, E, F dari kesamaan suku banyak
[tex]\displaystyle \frac{1}{(x+1)^2~(x^2+1)^2} =\frac{A}{x+1} +\frac{B}{(x+1)^2} +\frac{Cx+D}{x^2+1} +\frac{Ex+F}{(x^2+1)^2}[/tex]
[tex]\displaystyle \frac{1}{(x+1)^2~(x^2+1)^2} =\frac{A}{x+1} +\frac{B}{(x+1)^2} +\frac{Cx+D}{x^2+1} +\frac{Ex+F}{(x^2+1)^2}[/tex]