Question

Quiz
[tex](x - 5) ^{5} (x + 4)^{5} = (x - 2)^{10} [/tex]
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Answer 1

Verified answer

Materi : Bentuk Akar dan Pangkat, SPLSV

( x - 5 )⁵( x + 4 )⁵ = ( x - 2 )¹⁰

( x² - x - 20 )⁵ = ( x - 2 )¹⁰

x² - x - 20 = ⁵√( x - 2 )¹⁰

x² - x - 20 = ( x - 2 )²

x² - x - 20 = x² - 4x + 4

- x - 20 = - 4x + 4

4x - x = 20 + 4

3x = 24

x = 8

Semoga bisa membantu

[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]

Answer 2

Penyelesaian

(x-5)⁵(x+4)⁵=(x-2)¹⁰

((x-5)(x+4))⁵=(x-2)¹⁰

(x-5)(x+4)=(x-2)^10/5

x²-5x+4x-20=(x-2)²

x²-x-20=x²-4x+4

-x-20=-4x+4

-x+4x=4+20

3x=24

Jadi x=24/3=8

Semoga bermanfaat