Respuesta:
jdowbeiwbd9dnowbdidjeifbdowndofbodnd
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Solución al problema planteado //
[tex] \frac{ - 1}{3} - a = \frac{ - 1}{5} + \frac{3}{ {( - 2)}^{2} } [/tex]
[tex] - \frac{ 1}{3} - a = - \frac{1}{5} + \frac{3}{4} [/tex]
[tex] - \frac{1}{3} - a = \frac{ - 4 + 15}{20} [/tex]
[tex] - \frac{1}{3} - a = \frac{11}{20} [/tex]
[tex] - a = \frac{11}{20} + \frac{1}{3} [/tex]
[tex] - a = \frac{33 + 20}{60} [/tex]
[tex] - a = \frac{53}{60} [/tex]
Multiplicamos por su neutro (-1) a ambos miembros !
[tex] ( - 1) ( - a) = ( - 1)( \frac{53}{60} )[/tex]
[tex]a = - \frac{53}{60} [/tex]
Saludos y bendiciones
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Respuesta:
jdowbeiwbd9dnowbdidjeifbdowndofbodnd
Respuesta:
Hola buenas //
______________
Solución al problema planteado //
[tex] \frac{ - 1}{3} - a = \frac{ - 1}{5} + \frac{3}{ {( - 2)}^{2} } [/tex]
[tex] - \frac{ 1}{3} - a = - \frac{1}{5} + \frac{3}{4} [/tex]
[tex] - \frac{1}{3} - a = \frac{ - 4 + 15}{20} [/tex]
[tex] - \frac{1}{3} - a = \frac{11}{20} [/tex]
[tex] - a = \frac{11}{20} + \frac{1}{3} [/tex]
[tex] - a = \frac{33 + 20}{60} [/tex]
[tex] - a = \frac{53}{60} [/tex]
Multiplicamos por su neutro (-1) a ambos miembros !
[tex] ( - 1) ( - a) = ( - 1)( \frac{53}{60} )[/tex]
[tex]a = - \frac{53}{60} [/tex]
Saludos y bendiciones