#5.[tex] \\ [/tex]f(a) = a³ + a² + a!!f(2) = ...?[tex] \\ [/tex].... Question from @Ciyraa

Ciyraa @Ciyraa

August 2022 2 26 Report

#5.
[tex] \\ [/tex]
f(a) = a³ + a² + a!!
f(2) = ...?
[tex] \\ [/tex]

CallMeDijah

SOAL #5

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f(a) = a³ + a² + a!!

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f(2) = 2³ + 2² + 2!!

f(2) = (2.2.2) + (2.2) + 2

f(2) = (4.2) + (2.2) + 2

f(2) = 8 + 4 + 2

f(2) = 8 + 6

f(2) = 14

___________________________________________ $\colorbox{black}{\pink{\boxed{✿✧ \: \colorbox{black}{ \purple{\boxed{\tt{ \: \blue{❛❜ \: Dijah} \pink{ Canzz❛❜} \: }}}} \: ✧✿}}}$

0 votes Thanks 0

FaaCha

Jawaban:

$\tt \: f(a) = {a}^{3} + {a}^{2} + a!!$

$\tt \: f(2) = 14$

Penyelesaian =

$\tt \: f(a) = {a}^{3} + {a}^{2} +a!!$

$\tt \: f(2) = {2}^{3} + {a}^{2} +a!!$

$\tt \: f(2) = (2 \times 2 \times 2) + {a}^{2} + a!!$

$\tt \: f(2) = (4 \times 2) + {a}^{2} + a !!$

$\tt \: f(2) = 8 + {a}^{2} + a!!$

$\tt \: f(2) = 8 + {2}^{2} + a!!$

$\tt \: f(2) = 8 + (2 \times 2) + a!!$

$\tt \: f(2) = 8 + 4 + a!!$

$\tt \: f(2) = 12 + a!!$

$\tt \: f(2) = 12 + 2!!$

$\tt \: f(2) = 12 + (2 \times 1)$

$\tt \: f(2) = 14 + 2$

$\tt \: f(2) = \green1 \green4$

1 votes Thanks 0

FaaCha ehh

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