Penjelasan dengan langkah-langkah:
5.a
[tex]3x + x - 20 = 180 \\ 4x - 20 = 180 \\ 4x = 180 + 20 \\ x = \frac{200}{4} = 50[/tex]
b.
[tex] < abd = 3x = 3(50) = 150 [/tex]
c.
[tex] < dbc = x - 2 = 50 - 2 = 48[/tex]
6.a
[tex] < e = 110 \\ < f = 180 - 110 = 70 \\ < g = < f = 70[/tex]
b. luar berseberangan : <A=<H, <B=<G
c. sehadap : <A=<E, <B=<F, <C=<G, <D=<H
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Penjelasan dengan langkah-langkah:
5.a
[tex]3x + x - 20 = 180 \\ 4x - 20 = 180 \\ 4x = 180 + 20 \\ x = \frac{200}{4} = 50[/tex]
b.
[tex] < abd = 3x = 3(50) = 150 [/tex]
c.
[tex] < dbc = x - 2 = 50 - 2 = 48[/tex]
6.a
[tex] < e = 110 \\ < f = 180 - 110 = 70 \\ < g = < f = 70[/tex]
b. luar berseberangan : <A=<H, <B=<G
c. sehadap : <A=<E, <B=<F, <C=<G, <D=<H