Penjelasan dengan langkah-langkah:
² log abc - ( 2 : ³ log 2 ) = 7 + ² log 5
, syarat abc > 0
² log abc - ( 2 ²log3 ) = 7 + ² log 5
² log abc = 7 + ² log 5 + (2 ²log3)
² log abc = ² log 2⁷ + ² log 5 + ² log 3²
² log abc = ² log 128 + ² log 5 + ² log 9
² log abc = ² log ( 128 × 5 × 9)
² log abc = ² log 5760
abc = 5760
jika a > b > c , maka a = 128
jika b < a < c , maka a = 9
jika c > b > a , maka a = 5
jika b > a > c , maka b = 128
jika c < b < a , maka b = 9
jika a > c > b , maka b = 5
jika c > a > b , maka c = 128
jika a < c < b , maka c = 9
jika a > b > c , maka c = 5
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Penjelasan dengan langkah-langkah:
² log abc - ( 2 : ³ log 2 ) = 7 + ² log 5
, syarat abc > 0
² log abc - ( 2 ²log3 ) = 7 + ² log 5
² log abc = 7 + ² log 5 + (2 ²log3)
² log abc = ² log 2⁷ + ² log 5 + ² log 3²
² log abc = ² log 128 + ² log 5 + ² log 9
² log abc = ² log ( 128 × 5 × 9)
² log abc = ² log 5760
abc = 5760
jika a > b > c , maka a = 128
jika b < a < c , maka a = 9
jika c > b > a , maka a = 5
jika b > a > c , maka b = 128
jika c < b < a , maka b = 9
jika a > c > b , maka b = 5
jika c > a > b , maka c = 128
jika a < c < b , maka c = 9
jika a > b > c , maka c = 5