Q.(8/3)f(x) = 77x² - 77x² + 67xf(1b + 2b) = ..[tex] \\[/tex].... Question from @liahanindita58

May 2022 2 27 Report

Q.(8/3)

f(x) = 77x² - 77x² + 67x
f(1b + 2b) = ..
[tex] \\[/tex]

Nilai dari f(1b + 2b) adalah 201b.

Pembahasan:

$\boxed{\begin{aligned}\sf f(x) &=\sf 77x^2 - 77x^2 + 67x\\ \sf f(x)&=\sf 67x\\ \sf f(1b + 2b) &=\sf 67 \: (1b + 2b)\\ \sf f(1b + 2b)&= \sf 67 \: (3b)\\ \sf f(1b + 2b)&=\sf 201b\end{aligned}}$

Jadi, nilai dari f(1b + 2b) adalah 201b.

26 votes Thanks 39

XxDarknessxX

f ( x ) = 77x² - 77x² + 67x
f ( 1b + 2b ) = ( 77 - 77 )x² + 67x
f ( 1b + 2b ) = 0 + 67x
f ( 1b + 2b ) = 67x
67x
67 ( 1b + 2b )
67 ( ( 1 + 2 )b )
67 ( ( 3 ) b )
67 ( 3b )
67 × 3b
( 67 × 3 )b
( 201 )b
201b

$\purple{\boxed{\green{\boxed{\red{\tt{\ \: \red{{» By : \: XxDarknessxX࿐ }}}}}}}}$

7 votes Thanks 12

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