Question

[tex]x {}^{2} - 12 \times = 4[/tex]
[tex]x {}^{2} - 12 + - 4 = 0[/tex]
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Answer 1

x² −12x − 4 = 0
a= 1 b= −12 c= −4

D = b²− 4a c
D = (−12)² − 4×1×−4
D = 144 + 16 = 160

x= ( −b ± √D )/ (2a)
x = ( −(−12)± √160 )/ (2×1)
x= ( 12 ± 4√10 )/ 2
x= 6 ± 2√10

x₁ = 6−2√10 atau x₂= 6+2√10

Answer 2

Verified answer

X1 = 6+2 √10
X2 = 6-2 √10