Question

Q.

[tex]\bold{\mathfrak{\green{\bf \sf \tt Diketahui \: }}}[/tex]
[tex] \mathfrak{\bf \sf \tt f ( x ) = 54x + \sqrt{100} + x!! × x³ + \frac{36}{x}}[/tex]

[tex]\bold{\mathfrak{\green{\bf \sf \tt Ditanya \: }}}[/tex]
[tex] \mathfrak{\bf \sf \tt f ( 6 ) = ...?}[/tex]

⇲ Rules :
✎ No Calcu ☑︎
✎ No bahasa alien ☑︎
✎ No Jawab Dikomen ☑︎
✎ Memakai Cara ☑︎

[tex] _{angka \: yang \: cukup \: menarik \: :v}[/tex]
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Answer 1

SOAL Q.

f(x) = 54x + √100 + x!! × x³ + 36/x

f(6) = 54(6) + √10² + 6!! × 6³ + 36/6

f(6) = 324 + 10 + (6.4.2) × (6.6.6) + 6

f(6) = 324 + 10 + (24.2) × (36.6) + 6

f(6) = 324 + 10 + 48 × 216 + 6

f(6) = 324 + 10 + 10.368 + 6

f(6) = 324 + 10 + 10.374

f(6) = 324 + 10.384

f(6) = 10.708

I Hope This Help!