Respuesta:
[tex]6-x\ge \:2x+9\\6-x-6\ge \:2x+9-6\\-x\ge \:2x+3\\-x-2x\ge \:2x+3-2x\\-3x\ge \:3\\\left(-3x\right)\left(-1\right)\le \:3\left(-1\right)\\\frac{3x}{3}\le \frac{-3}{3}\\x\le \:-1\\[/tex]
[tex]6 - x \geqslant 2x + 9 \\ - x - 2x \geqslant 9 - 6 \\ - 3x \geqslant 3 \\ \bf \: x \leqslant - 1[/tex]
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Verified answer
Respuesta:
[tex]6-x\ge \:2x+9\\6-x-6\ge \:2x+9-6\\-x\ge \:2x+3\\-x-2x\ge \:2x+3-2x\\-3x\ge \:3\\\left(-3x\right)\left(-1\right)\le \:3\left(-1\right)\\\frac{3x}{3}\le \frac{-3}{3}\\x\le \:-1\\[/tex]
F<3
[tex]6 - x \geqslant 2x + 9 \\ - x - 2x \geqslant 9 - 6 \\ - 3x \geqslant 3 \\ \bf \: x \leqslant - 1[/tex]