Respuesta:
1). [tex]=-\frac{8}{125}[/tex]
2). [tex]=-29\sqrt[3]{\frac{4}{3}}[/tex]
Explicación paso a paso:
[tex]=\frac{\left(-\frac{2}{5}\right)^{10}}{\left(-\frac{2}{5}\right)^7\left(-\frac{2}{5}\right)^0}[/tex] [tex]=29\sqrt[3]{-\frac{4}{3}}[/tex]
[tex]=\frac{\left(-\frac{2}{5}\right)^{10}}{\left(-\frac{2}{5}\right)^7\cdot \:1}[/tex] [tex]=29\left(-\sqrt[3]{\frac{4}{3}}\right)[/tex]
[tex]=\frac{\left(-\frac{2}{5}\right)^{10}}{\left(-\frac{2}{5}\right)^7\cdot \:1}[/tex] [tex]=-29\sqrt[3]{\frac{4}{3}}[/tex]
[tex]=\left(-\frac{2}{5}\right)^{10-7}[/tex]
[tex]=\left(-\frac{2}{5}\right)^3[/tex]
[tex]=-\frac{8}{125}[/tex]
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Verified answer
Respuesta:
1). [tex]=-\frac{8}{125}[/tex]
2). [tex]=-29\sqrt[3]{\frac{4}{3}}[/tex]
Explicación paso a paso:
[tex]=\frac{\left(-\frac{2}{5}\right)^{10}}{\left(-\frac{2}{5}\right)^7\left(-\frac{2}{5}\right)^0}[/tex] [tex]=29\sqrt[3]{-\frac{4}{3}}[/tex]
[tex]=\frac{\left(-\frac{2}{5}\right)^{10}}{\left(-\frac{2}{5}\right)^7\cdot \:1}[/tex] [tex]=29\left(-\sqrt[3]{\frac{4}{3}}\right)[/tex]
[tex]=\frac{\left(-\frac{2}{5}\right)^{10}}{\left(-\frac{2}{5}\right)^7\cdot \:1}[/tex] [tex]=-29\sqrt[3]{\frac{4}{3}}[/tex]
[tex]=\left(-\frac{2}{5}\right)^{10-7}[/tex]
[tex]=\left(-\frac{2}{5}\right)^3[/tex]
[tex]=-\frac{8}{125}[/tex]