[tex]\begin{aligned}&\textsf{Jika }x^{\frac{1}{2}} + x^{-\frac{1}{2}} = 3,\\&\textsf{maka nilai dari }x+x^{-1}\\&\sf adalah\ \boxed{\,\bf7\,}\ .\end{aligned}[/tex]
Eksponen
Diketahui:
[tex]\begin{aligned}x^{\frac{1}{2}} + x^{-\frac{1}{2}} = 3\end{aligned}[/tex]
Ditanyakan:
[tex]x+x^{-1}=...?[/tex]
Penyelesaian
Ingat a² + b² = (a + b)² – 2ab.
Maka:
[tex]\begin{aligned}x+x^{-1}&=\left(x^{\frac{1}{2}}\right)^2 + \left(x^{-\frac{1}{2}}\right)^2\\&=\left(x^{\frac{1}{2}} + x^{-\frac{1}{2}}\right)^2-2x^{\frac{1}{2}}x^{-\frac{1}{2}}\\&=\left(x^{\frac{1}{2}} + x^{-\frac{1}{2}}\right)^2-2x^{\frac{1}{2}-\frac{1}{2}}\\&=\left(x^{\frac{1}{2}} + x^{-\frac{1}{2}}\right)^2-2x^0\\&=\left(x^{\frac{1}{2}} + x^{-\frac{1}{2}}\right)^2-2\\&=3^2-2\\x+x^{-1}&=\boxed{\,\bf7\,}\quad\blacksquare\end{aligned}[/tex]
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[tex]\begin{aligned}&\textsf{Jika }x^{\frac{1}{2}} + x^{-\frac{1}{2}} = 3,\\&\textsf{maka nilai dari }x+x^{-1}\\&\sf adalah\ \boxed{\,\bf7\,}\ .\end{aligned}[/tex]
Penjelasan dengan langkah-langkah:
Eksponen
Diketahui:
[tex]\begin{aligned}x^{\frac{1}{2}} + x^{-\frac{1}{2}} = 3\end{aligned}[/tex]
Ditanyakan:
[tex]x+x^{-1}=...?[/tex]
Penyelesaian
Ingat a² + b² = (a + b)² – 2ab.
Maka:
[tex]\begin{aligned}x+x^{-1}&=\left(x^{\frac{1}{2}}\right)^2 + \left(x^{-\frac{1}{2}}\right)^2\\&=\left(x^{\frac{1}{2}} + x^{-\frac{1}{2}}\right)^2-2x^{\frac{1}{2}}x^{-\frac{1}{2}}\\&=\left(x^{\frac{1}{2}} + x^{-\frac{1}{2}}\right)^2-2x^{\frac{1}{2}-\frac{1}{2}}\\&=\left(x^{\frac{1}{2}} + x^{-\frac{1}{2}}\right)^2-2x^0\\&=\left(x^{\frac{1}{2}} + x^{-\frac{1}{2}}\right)^2-2\\&=3^2-2\\x+x^{-1}&=\boxed{\,\bf7\,}\quad\blacksquare\end{aligned}[/tex]