Question

[tex]^alog(b-18)=2\\^blog(a+3)=\frac{1}{2}\\b-a=....[/tex]

Answer 1

Jawaban:

75/4

Penjelasan dengan langkah-langkah:

Berarti:

Masukkan:

a²+6a+9-18= a²

6a-9= 0

6a= 9

a= 3/2.

b= (3/2)²+6(3/2)+9

= 9/4 + 9 + 9

= 18 + 9/4

= 81/4

b-a

= 81/4 - 3/2

= 81/4 - 6/4

= 75/4

Answer 2

Penjelasan dengan langkah-langkah:

^a log (b ·– 18) = 2

^a log (b ·– 18) = ^a log a²

b – 18 = a²

b = a² + 18 ....... ♣

^b log (a + 3) = ½

^b log (a + 3) = ^b log b^½

a + 3 = √b

b = (a + 3)²

b = a² + 6a + 9 .... ♥

♥ = ♣

a² + 6a + 9 = a² + 18

a² – a² + 6a = 18 – 9

6a = 9

a = 3/2

a = 1,5 ✔

♣ b = a² + 18

b = (3/2)² + 18

b = 9/4 + 18

b = 20¼

b = 20,25 ✔

Penyelesaian :

b – a = 20,25 – 1,5

b – a = 18,25 + 2 – 1,5

b – a = 18,25 + 0,5

b – a = 18,75 ✔✔