Jawaban:
π ∫ 2xr - x² dx [2r - 0]
= π [2rx²/2 - x³/3 ] [2r]
= π [r(2r)² - (2r)³/3]
= π [r(4r²) - 8r³/3]
= π (4r³ - 8r³/3)
= π (12r³/3 - 8r³/3)
= π (4/3 r³)
= 4/3 πr³
(d) Volume Bola
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Jawaban:
π ∫ 2xr - x² dx [2r - 0]
= π [2rx²/2 - x³/3 ] [2r]
= π [r(2r)² - (2r)³/3]
= π [r(4r²) - 8r³/3]
= π (4r³ - 8r³/3)
= π (12r³/3 - 8r³/3)
= π (4/3 r³)
= 4/3 πr³
(d) Volume Bola