Question

[tex]Jika \\ \ \textless \ br /\ \textgreater \ {2}^{x} . { {4}^{3} }^{y} = 8 \\ \ \textless \ br /\ \textgreater \ maka nilai \\ \ \textless \ br /\ \textgreater \ \frac{1}{3}x+2y= \\ [/tex]
a. 1
b. 2
c. 3
d. 4

Mohon bantuannya ya kak​​

Answer 1

Verified answer

Jawaban:

aljabar, eksponen

[tex] {2}^{x} \: . \: {4}^{3y} = 8 \\ {2}^{x} \: . \: ( {2}^{2} ) {}^{3y} = {2}^{3} \\ {2}^{x} \: . \: {2}^{6y} = {2}^{3} \\ x + 6y = 3[/tex]

[tex]x + 6y = 3 \: kalikan \: kedua \: ruas \: sama \: dgn \: \times \frac{1}{3} \\ [/tex]

[tex]x + 6y = 3 \\ \frac{1}{3} .x + \frac{1}{3} .6y = \frac{1}{3} .3 \\ \frac{1}{3} x + 2y = 1[/tex]