3! + 20³ + √729 = ..
[tex] \\ \\ [/tex]
f(x) = x!! + 30x + x²
f(5) = ..
[tex] \\ [/tex]
[tex] \\ \\ [/tex]
f(x) = x!! + 30x + x²
f(5) = ..
[tex] \\ [/tex]
muhammadpedroza684
3! + 20³ + √729= ( 3 × 2 × 1 ) + (( 20 × 20 ) × 20 )) + 27= ( 6 × 1 ) + ( 400 × 20 ) + 27= 6 + 8000 + 27= 8006 + 27= 8.033f(x) = x!! + 30x + x²f(5) = 5!! + 30(5) + 5²f(5) = ( 5 × 3 × 1 ) + ( 30 × 5 ) + ( 5 × 5 )f(5) = ( 15 × 1 ) + 150 + 25f(5) = 15 + 150 + 25f(5) = 165 + 25f(5) = 190⃢~ Opung~⃠⃫⃟⃤᳗᳐
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