Question

⁷log 343 + 22² × 11^0 = ..
[tex] \\ \\ \\ [/tex]
Lim (x³ × 50x)
x → 10
[tex] \\ \\ [/tex]
​

Answer 1

Math_

⁷log 343 + 22² × 11⁰

= ⁷log 7³ + (22 × 22) × 1

= 3 + 484 × 1

= 3 + 484

= 487

__

Lim (x³ × 50x)

x => 10

= (10)³ × 50(10)

= (10 × 10 × 10) × 50(10)

= 1.000 × 50(10)

= 50.000(10)

= 500.000

cmiiw

Answer 2

⁷log 343 + 22² × 11^0

= ⁷log 7³ + (22 × 22) × 1

= (3 × ⁷log 7) + 484

= (3 × 1) + 484

= 3 + 484

= 487

...

lim (x³ + 50x)

x → 10

= (10³ + 5(10))

= (1.000 + 500)

= 1.500